SELECT my_key, count(*) FROM my_table GROUP BY my_key HAVING count(*) > 1;
November 11, 2009
Find duplicate in a database
April 7, 2009
Draw a rectangle on an image
convert -draw “rectangle x0 y0 x1 y1″ -fill none -stroke red -strokewidth 5
SELECT my_key, count(*) FROM my_table GROUP BY my_key HAVING count(*) > 1;
convert -draw “rectangle x0 y0 x1 y1″ -fill none -stroke red -strokewidth 5